A) 1500 K
B) 2000 K
C) 2500 K
D) 3000 K
Correct Answer: B
Solution :
\[{{\lambda }_{m}}T=b\] where \[b=2.89\times {{10}^{-3}}mK\] Þ \[T=\frac{b}{{{\lambda }_{m}}}=\frac{2.89\times {{10}^{-3}}}{1.5\times {{10}^{-6}}}\]\[\approx 2000K\]You need to login to perform this action.
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