A)
B)
C)
D)
Correct Answer: A
Solution :
According to ohm's law \[V=iR\] Þ \[{{\log }_{e}}V={{\log }_{e}}i+{{\log }_{e}}R\] Þ \[{{\log }_{e}}i={{\log }_{e}}V-{{\log }_{e}}R\] The graph between \[{{\log }_{e}}I\] and \[{{\log }_{e}}V\] will be a straight line which cut \[{{\log }_{e}}V\] axis and it's gradient will be positive.
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