A) \[qEa\]
B) \[-qEa\]
C) \[qEa\sqrt{2}\]
D) \[qE\sqrt{[{{(2a)}^{2}}+{{b}^{2}}]}\]
Correct Answer: B
Solution :
As electric field is a conservative field Hence the work done does not depend on path \ \[{{W}_{ABCD}}={{W}_{AOD}}\] \[={{W}_{AO}}+{{W}_{OD}}\] \[=Fb\text{cos 9}{{0}^{\text{o}}}+Fa\text{cos18}{{0}^{\text{o}}}=0+qEa\left( \text{1} \right)=qEa\]You need to login to perform this action.
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