A) \[\cos 2\theta \]
B) \[\sin \theta \]
C) \[\cot 2\theta \]
D) \[\tan \theta \]
Correct Answer: C
Solution :
As we know, for conductors resistance µ Temperature. From figure R1 µ T1 Þ tanq µ T1 Þ tanq = kT1 ? (i) and R2 µ T2 Þ tan (90o ? q) µ T2 Þ cotq = kT2 ?.(ii) From equation (i) and (ii) \[k({{T}_{2}}-{{T}_{1}})=(\cot \theta -\tan \theta )\,\] \[\,({{T}_{2}}-{{T}_{1}})=\left( \frac{\cos \theta }{\sin \theta }-\frac{\sin \theta }{\cos \theta } \right)=\frac{({{\cos }^{2}}\theta -{{\sin }^{2}}\theta )}{\sin \theta \cos \theta }\]\[=2\cot 2\theta \] Þ (T2 ? T1) µ cot 2q
You need to login to perform this action.
You will be redirected in
3 sec
