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JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Graphical Questions

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    A force \[F\]acting on an object varies with distance \[x\]as shown here. The force is in newton and \[x\] in metre. The work done by the force in moving the object from \[x=0\]to \[x=6m\] is [CBSE PMT 2005]            

    A)                         4.5 J            

    B)                         13.5 J

    C)                         9.0 J            

    D)                         18.0 J

    Correct Answer: B

    Solution :

                    Work done = Area enclosed by F ? x graph             \[=\frac{1}{2}\times (3+6)\times 3=13.5\,\,J\]          


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