A)
B)
C)
D)
Correct Answer: B
Solution :
Let resistivity at a distance 'x' from left end be \[\rho =({{\rho }_{0}}+ax).\] Then electric field intensity at a distance 'x' from left end will be equal to \[E=\frac{i\rho }{A}=\frac{i({{\rho }_{0}}+ax)}{A}\] where i is the current flowing through the conductor. It means \[E\propto \rho \] or E varies linearly with distance 'x'. But at x = 0, E has non-zero value. Hence is correct.
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