A)
B)
C)
D)
Correct Answer: C
Solution :
\[\frac{d\theta }{dt}=\frac{\varepsilon A\sigma }{mc}4\theta _{0}^{3}\Delta \theta \] For given sphere and cube \[\frac{\varepsilon A\sigma }{mc}4\theta _{0}^{3}\Delta \theta \] is constant so for both rate of fall of temperature \[\frac{d\theta }{dt}=\]constant
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