JEE Main & Advanced Physics Transmission of Heat Question Bank Graphical Questions

  • question_answer
    In the figure, the distribution of energy density of the radiation emitted by a black body at a given temperature is shown. The possible temperature of the black body is

    A)            1500 K                                     

    B)            2000 K

    C)            2500 K                                     

    D)            3000 K 

    Correct Answer: B

    Solution :

                       \[{{\lambda }_{m}}T=b\] where  \[b=2.89\times {{10}^{-3}}mK\] Þ \[T=\frac{b}{{{\lambda }_{m}}}=\frac{2.89\times {{10}^{-3}}}{1.5\times {{10}^{-6}}}\]\[\approx 2000K\]


You need to login to perform this action.
You will be redirected in 3 sec spinner