A)
B)
C)
D)
Correct Answer: C
Solution :
\[N={{N}_{0}}{{e}^{-\lambda t}}\]Þ \[\frac{dN}{dt}=-{{N}_{0}}\lambda {{e}^{-\lambda t}}\] i.e. Rate of decay \[\left( \frac{dN}{dt} \right)\] varies exponentially with time (t).You need to login to perform this action.
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