A)
B)
C)
D)
Correct Answer: A
Solution :
\[R={{R}_{0}}{{A}^{1/3}};\] where \[{{R}_{0}}=1.2\times {{10}^{-15}}m.\] Þ loge R = loge R0 +\[\frac{1}{3}{{\log }_{e}}A\] This is the equation of a straight line with positive slope.You need to login to perform this action.
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