A) Elasticity of wire P is maximum
B) Elasticity of wire Q is maximum
C) Tensile strength of R is maximum
D) None of the above is true
Correct Answer: D
Solution :
As stress is shown on x-axis and strain on y-axis So we can say that \[Y=\cot \theta =\frac{1}{\tan \theta }=\frac{1}{\text{slope}}\] So elasticity of wire P is minimum and of wire R is maximumYou need to login to perform this action.
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