A) \[6.6\times {{10}^{-31}}\] J-sec
B) \[6.6\times {{10}^{-34}}\]J-sec
C) \[9.1\times 10-31\] J-sec
D) None of these
Correct Answer: B
Solution :
Slope of \[{{V}_{0}}-\nu \] curve \[=\frac{h}{e}\] Þ h = Slope ´ e = 1.6 ´ 10?19´ 4.12 ´ 10?15 \[=6.6\times {{10}^{-34}}\,J\text{-}\sec \].You need to login to perform this action.
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