JEE Main & Advanced Physics Thermodynamical Processes Question Bank Graphical Questions

  • question_answer
    In the cyclic process shown in the figure, the work done by the gas in one cycle is                                                [MP PMT 1999]

    A)            \[28\,{{P}_{1}}{{V}_{1}}\]

    B)            \[14\,{{P}_{1}}{{V}_{1}}\]

    C)            \[18\,{{P}_{1}}{{V}_{1}}\]

    D)            \[9\,{{P}_{1}}{{V}_{1}}\]

    Correct Answer: D

    Solution :

               Work done = Area under curve \[=\frac{6{{P}_{1}}\times 3{{V}_{1}}}{2}\]= 9 P1V1


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