Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति
JEE Main & Advanced
Physics
Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति
Question Bank
Graphical Questions
question_answer
A force \[F\]acting on an object varies with distance \[x\]as shown here. The force is in newton and \[x\] in metre. The work done by the force in moving the object from \[x=0\]to \[x=6m\] is [CBSE PMT 2005]
A) 4.5 J
B) 13.5 J
C) 9.0 J
D) 18.0 J
Correct Answer:
B
Solution :
Work done = Area enclosed by F ? x graph \[=\frac{1}{2}\times (3+6)\times 3=13.5\,\,J\]