A)
B)
C)
D)
Correct Answer: C
Solution :
\[P=\sqrt{2mE}\] it is clear that \[P\propto \sqrt{E}\] So the graph between P and \[\sqrt{E}\] will be straight line. but graph between \[\frac{1}{P}\] and \[\sqrt{E}\] will be hyperbolaYou need to login to perform this action.
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