JEE Main & Advanced Physics Thermodynamical Processes Question Bank Graphical Questions

  • question_answer
    A system is taken through a cyclic process represented by a circle as shown. The heat absorbed by the system is

    A)             \[\pi \times {{10}^{3}}J\]

    B)             \[\frac{\pi }{2}J\]

    C)             \[4\pi \times {{10}^{2}}J\]

    D)             \[\pi \,J\]

    Correct Answer: B

    Solution :

                       In cyclic process DQ = Work done = Area inside the closed curve. Treat the circle as an ellipse of area \[=\frac{\pi }{4}({{P}_{2}}-{{P}_{1}})\,({{V}_{2}}-{{V}_{1}})\] Þ \[\Delta Q=\frac{\pi }{4}\{(150-50)\times {{10}^{3}}\}=\frac{\pi }{2}J\]


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