A) \[{{P}_{0}}{{V}_{0}}\]
B) \[2{{P}_{0}}{{V}_{0}}\]
C) \[\frac{{{P}_{0}}{{V}_{0}}}{2}\]
D) Zero
Correct Answer: D
Solution :
WBCOB = ? Area of triangle BCO \[=-\frac{{{P}_{0}}{{V}_{0}}}{2}\] WAODA = + Area of triangle AOD \[=+\frac{{{P}_{0}}{{V}_{0}}}{2}\]
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