JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Graphical Questions

  • question_answer
    A particle is placed at the origin and a force \[F=kx\]is acting on it (where k is positive constant). If \[U(0)=0\], the graph of \[U(x)\] versus x will be (where U is the potential energy function)   [IIT-JEE (Screening) 2004]

    A)

    B)

    C)

    D)

    Correct Answer: A

    Solution :

                    \[U=-\int_{{}}^{{}}{Fdx=-\int_{{}}^{{}}{kx\ dx=-k\frac{{{x}^{2}}}{2}}}\]             This is the equation of parabola symmetric to U axis in negative direction


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