A) 2PV
B) PV
C) 1/2PV
D) Zero
Correct Answer: A
Solution :
Work done = Area enclosed by triangle ABC\[=\frac{1}{2}AC\times BC=\frac{1}{2}\times (3V-V)\times (3P-P)=2\,PV\]You need to login to perform this action.
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