A) 32,000 K
B) 16,000 K
C) 8,000 K
D) 4,000 K
Correct Answer: D
Solution :
\[\frac{{{A}_{T}}}{{{A}_{2000}}}=\frac{16}{1}\] (given) Area under \[{{e}_{\lambda }}-\lambda \] curve represents the emissive power of body and emissive power \[\propto {{T}^{4}}\] (Hence area under \[{{e}_{\lambda }}-\lambda \] curve) \[\propto {{T}^{4}}\] Þ\[\frac{AT}{{{A}_{2000}}}={{\left( \frac{T}{2000} \right)}^{4}}\]Þ \[\frac{16}{1}={{\left( \frac{T}{2000} \right)}^{4}}\]Þ \[T=4000K.\]
You need to login to perform this action.
You will be redirected in
3 sec
