A) \[\frac{mu}{T}\]
B) \[\frac{2mu}{T}\]
C) \[\frac{4mu}{3T}\]
D) \[\frac{3mu}{4T}\]
Correct Answer: C
Solution :
Change in momentum = Impulse = Area under force-time graph \ \[mv=\]Area of trapezium Þ \[mv=\frac{1}{2}\left( T+\frac{T}{2} \right)\ {{F}_{0}}\] Þ \[mv=\frac{3T}{4}{{F}_{0}}\]Þ\[{{F}_{0}}=\frac{4mu}{3T}\]You need to login to perform this action.
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