A)
B)
C)
D)
Correct Answer: C
Solution :
As RC time constant of the capacitor is quite large (\[\tau =RC=10\times {{10}^{3}}\times 10\times {{10}^{-6}}=0.1\,sec\]), if will not discharge appreciably. Hence voltage remains nearly constant.You need to login to perform this action.
You will be redirected in
3 sec