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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Graphical Questions

  • question_answer
    The graph shows the variation of displacement of a particle executing S.H.M. with time. We infer from this graph that

    A)            The force is zero at time \[3T/4\]

    B)            The velocity is maximum at time \[T/2\]

    C)            The acceleration is maximum at time T

    D)            The P.E. is equal to total energy at time \[T/2\]

    Correct Answer: D

    Solution :

               At time \[\frac{T}{2};\ v=0\] \[\therefore \]Total energy = Potential energy.


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