JEE Main & Advanced Physics Thermodynamical Processes Question Bank Graphical Questions

  • question_answer
    In the following P-V diagram two adiabatics cut two isothermals at temperatures T1 and T2 (fig.). The value of \[\frac{{{V}_{a}}}{{{V}_{d}}}\] will be 

    A)            \[\frac{{{V}_{b}}}{{{V}_{c}}}\]                                          

    B)            \[\frac{{{V}_{c}}}{{{V}_{b}}}\]

    C)            \[\frac{{{V}_{d}}}{{{V}_{a}}}\]                                          

    D)            \[{{V}_{b}}{{V}_{c}}\]

    Correct Answer: A

    Solution :

                       For adiabatic process \[{{T}_{1}}V_{b}^{\gamma -1}\]= Constant                    For bc curve \[{{T}_{1}}V_{b}^{\gamma -1}={{T}_{2}}V_{c}^{\gamma -1}\] or \[\frac{{{T}_{2}}}{{{T}_{1}}}={{\left( \frac{{{V}_{b}}}{{{V}_{c}}} \right)}^{\gamma -1}}\]  ?..(i)                    For ad curve \[{{T}_{1}}V_{a}^{\gamma -1}={{T}_{2}}V_{d}^{\gamma -1}\] or \[\frac{{{T}_{2}}}{{{T}_{1}}}={{\left( \frac{{{V}_{a}}}{{{V}_{d}}} \right)}^{\gamma -1}}\]  ?..(ii) From equation (i) and (ii) \[\frac{{{V}_{b}}}{{{V}_{c}}}=\frac{{{V}_{a}}}{{{V}_{d}}}\]


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