A)
B)
C)
D)
Correct Answer: B
Solution :
\[{{V}_{inside}}=\frac{Q}{4\pi {{\varepsilon }_{0}}R}\] for \[r\le R\] ....(i) and \[{{V}_{out}}=\frac{Q}{4\pi {{\varepsilon }_{0}}r}\] for \[r\ge R\] ....(ii) i.e. potential inside the hollow spherical shell is constant and outside varies according to \[V\propto \frac{1}{r}\].
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