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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Graphical Questions

  • question_answer
    Which of the following graphs correctly represents the variation of \[\beta =-(dV/dP)/V\] with P for an ideal gas at constant temperature                              [IIT-JEE (Screening) 2002]

    A)                            

    B)                             

    C)                           

    D)                    

    Correct Answer: A

    Solution :

                       For an isothermal process PV = constant Þ \[PdV+VdP=0\] Þ \[-\frac{1}{V}\left( \frac{dV}{dP} \right)=\frac{1}{P}\] So, \[\beta =\frac{1}{P}\] \ graph will be rectangular hyperbola.


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