A) \[8\times {{10}^{-2}}joules\]
B) \[16\times {{10}^{-2}}joules\]
C) \[4\times {{10}^{-4}}joules\]
D) \[1.6\times {{10}^{-3}}joules\]
Correct Answer: A
Solution :
Work done = Area covered in between force displacement curve and displacement axis = Mass ´ Area covered in between acceleration-displacement curve and displacement axis. = \[10\times \frac{1}{2}(8\times {{10}^{-2}}\times 20\times {{10}^{-2}})\] = \[8\times {{10}^{-2}}\,J\]
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