A) \[{{y}_{\max }}=20m\]
B) \[{{y}_{\max }}=15m\]
C) \[{{y}_{\max }}=11m\]
D) \[{{y}_{\max }}=5m\]
Correct Answer: C
Solution :
Work done = Gain in potential energy Area under curve = mgh Þ \[\frac{1}{2}\times 11\times 100=5\times 10\times h\] Þ \[h=11m\]
You need to login to perform this action.
You will be redirected in
3 sec
