JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Graphical Questions

  • question_answer
    The graph between the resistive force F acting on a body and the distance covered by the body is shown in the figure. The mass of the body is 25 kg and initial velocity is 2 m/s. When the distance covered by the body is 4m, its kinetic energy would be

    A)                         50 J                

    B)                         40 J                

    C)                         20 J            

    D)                         10 J            

    Correct Answer: D

    Solution :

                                Initial K.E. of the body = \[\frac{1}{2}m{{v}^{2}}=\frac{1}{2}\times 25\times 4=50\,\,J\] Work done against resistive force = Area between F-x graph = \[\frac{1}{2}\times 4\times 20=40J\] Final K.E. = Initial K.E. ? Work done against resistive force                =\[50-40=10\,\,J\]


You need to login to perform this action.
You will be redirected in 3 sec spinner