JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Graphical Questions

  • question_answer
                       Figure A shows two capacitors connected in series and joined to a battery. The graph in figure B shows the variation in potential as one moves from left to right on the branch containing the capacitors, if    [MP PMT 1999]

    A)            \[{{C}_{1}}>{{C}_{2}}\]

    B)                    \[{{C}_{1}}={{C}_{2}}\]

    C)                    \[{{C}_{1}}<{{C}_{2}}\]

    D)                                      The information is not sufficient to decide the relation between \[{{C}_{1}}\]and \[{{C}_{2}}\]

    Correct Answer: C

    Solution :

               According to graph we can say that potential difference across the capacitor \[{{C}_{1}}\] is more than that across \[{{C}_{2}}\]. Since charge Q is same i.e., \[Q={{C}_{1}}{{V}_{1}}={{C}_{2}}{{V}_{2}}\]  Þ  \[\frac{{{C}_{1}}}{{{C}_{2}}}=\frac{{{V}_{2}}}{{{V}_{1}}}\] Þ   \[{{C}_{1}}<{{C}_{2}}\]       \[({{V}_{1}}>{{V}_{2}}).\]


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