JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Graphical Questions

  • question_answer
    A particle of mass 0.1 kg is subjected to a force which varies with distance as shown in fig. If it starts its journey from rest at \[x=0\], its velocity at \[x=12\,m\] is         [AIIMS 1995]

    A)                         0 m/s            

    B)                         \[20\sqrt{2}\,m/s\]            

    C)                         \[20\sqrt{3}\,m/s\]            

    D)                         \[40\,\,m/s\]            

    Correct Answer: D

    Solution :

                                Area between curve and displacement axis             = \[\frac{1}{2}\times (12+4)\times 10\]= 80 J             In this time body acquire kinetic energy = \[\frac{1}{2}m{{v}^{2}}\]             by the law of conservation of energy             \[\frac{1}{2}m{{v}^{2}}=80J\]             Þ \[\frac{1}{2}\times 0.1\times {{v}^{2}}=80\]             Þ v2 = 1600             Þ v = 40 m/s


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