A) \[1:4:9\]
B) \[1:2:3\]
C) \[1:9:25\]
D) \[1:3:5\]
Correct Answer: D
Solution :
\[{{s}_{n}}=u+a\left[ n-\frac{1}{2} \right]\] For a freely falling body,\[u=0\]and\[a=+g\],\[\therefore {{S}_{1}}:{{S}_{2}}:{{S}_{3}}=\] \[\frac{1}{2}g{{(1)}^{2}}:\left( \frac{1}{2}g{{(2)}^{2}}-\frac{1}{2}g{{(1)}^{2}} \right):\left( \frac{1}{2}g{{(3)}^{2}}-\frac{1}{2}g{{(2)}^{2}} \right)\]
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