A) \[\sqrt{3}\]
B) \[\frac{2{{u}^{2}}}{9}\]
C) \[\frac{3{{u}^{2}}}{9}\]
D) \[\frac{4{{u}^{2}}}{9}\]
Correct Answer: D
Solution :
\[{{v}^{2}}-{{u}^{2}}=2as,\,\,v=3u,\,\,a=-g,\,\,s=-h\] \[\therefore \]\[{{(3u)}^{2}}-{{u}^{2}}=2(-g)(-h)\] \[\Rightarrow \]\[8{{u}^{2}}=2gh\Rightarrow h=\frac{4{{u}^{2}}}{g}\]
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