A) \[1s\]
B) \[2s\]
C) \[3s\]
D) \[4s\]
Correct Answer: A
Solution :
Distance travelled by the wooden block before it meets the bullet\[={{s}_{1}}\] Distance travelled by the bullet before it meets the block\[={{s}_{2}}\] Height of the tower \[={{s}_{1}}+{{s}_{2}}=100\,\,m,\,\,{{t}_{1}}={{t}_{2}}=t\] For the wooden block: \[{{S}_{1}}=\frac{1}{2}g{{t}^{2}}=\frac{1}{2}\times 9.8\times {{t}^{2}}=4.9\,\,{{t}^{2}}\] For the bullet: \[{{S}_{2}}=ut-\frac{1}{2}g{{t}^{2}}=100t-\frac{1}{2}\times 9.8\times {{t}^{2}}\] Since,\[{{s}_{1}}+{{s}_{2}}=100\,\,m.\Rightarrow t=1\,\,s\]
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