A) \[4.9\,\,m\]
B) \[2.45\,\,m\]
C) \[9.8\,\,m\]
D) \[9\,\,m\]
Correct Answer: B
Solution :
\[S=ut+\frac{1}{2}g{{t}^{2}}\], so\[u=0\] \[\frac{1}{2}s=0\left( \frac{1}{2} \right)+\frac{1}{2}\times 9.8{{\left( \frac{1}{2} \right)}^{2}}\], \[\frac{1}{2}s=4.9\times \frac{1}{4}\] \[S=4.9\times \frac{1}{4}\times \frac{2}{1}=2.45\,\,m\]
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