A) \[11.14\times {{10}^{-18}}N\]
B) \[2.39\times {{10}^{-45}}N\]
C) \[1.86\times {{10}^{-44}}N\]
D) \[4.18\times {{10}^{-23}}N\]
Correct Answer: C
Solution :
\[F=\frac{G{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}\] \[=\frac{6.67\times {{10}^{-11}}\times 1.67\times {{10}^{-27}}\times 1.67\times {{10}^{-27}}}{{{\left( {{10}^{-10}} \right)}^{2}}}\] \[=18.6\times {{10}^{-45}}N=1.86\times {{10}^{-44}}N\]You need to login to perform this action.
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