A) 3 cm.
B) 6 cm.
C) 9 cm.
D) 10 cm.
Correct Answer: B
Solution :
Here, \[{{m}_{1}}=40kg,\,\,{{m}_{2}}=60kg,\] \[F=4\times {{10}^{-5}}N,\,\,G=6\times {{10}^{-11}}N{{m}^{2}}/k{{g}^{2}}.\] As \[F=G\frac{{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}\] \[r=\sqrt{\frac{G{{m}_{1}}{{m}_{2}}}{F}}\] \[=\sqrt{\frac{6\times {{10}^{-11}}\times 40\times 60}{4\times {{10}^{-5}}}}\] \[=\sqrt{36\times {{10}^{-4}}}=6\times {{10}^{-2}}m\] \[=6\times {{10}^{-2}}\times 100\,cm=6cm.\]You need to login to perform this action.
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