A) 250 N
B) 1000 N
C) 100 N
D) 2500 N
Correct Answer: A
Solution :
\[{{w}_{1}}=mg,\,\,{{g}_{1}}=\frac{g{{R}^{2}}}{{{(R+h)}^{2}}}=\frac{g}{{{\left( 1+\frac{h}{R} \right)}^{2}}}\] \[=\frac{10}{{{\left( 1+\frac{6400}{6400} \right)}^{2}}}=\frac{10}{4}2.5m/s\] \[\therefore {{w}_{1}}=100\times 2.5=250N\]You need to login to perform this action.
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