A) \[\frac{4R}{5}\]
B) \[\frac{R}{5}\]
C) \[\frac{R}{6}\]
D) \[\frac{R}{4}\]
Correct Answer: D
Solution :
\[{{w}_{1}}=\frac{6400}{100}\Rightarrow {{g}_{1}}=\frac{64g}{100},={{g}_{1}}=\frac{g{{R}^{2}}}{{{(R+h)}^{2}}}\] \[\Rightarrow \frac{64g}{100}=\frac{{{g}_{1}}}{\left( 1+\frac{h}{R} \right)}\Rightarrow 8h=2R\Rightarrow h=\frac{R}{4}\] \[8(R+h)=10R\Rightarrow 8h=2R\Rightarrow h=\frac{R}{4}\]You need to login to perform this action.
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