Answer:
\[-h=ut-\frac{1}{2}g{{t}^{2}}\] Hence \[-50=15\times t-\frac{1}{2}\times 10{{t}^{2}}\] \[5{{t}^{2}}-15t-50=0\,\,or\,\,{{t}^{2}}-3t-10=0\] \[\therefore \,\,(t=5)(t+2)=0\,\,or\,\,t=5s\]
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