question_answer

In the above problem, what is the distance between the body and the balloon 4 seconds after the body is dropped?

Answer:

In 4 seconds, balloon goes up 60 m. Let the body goes down S Where \[-S=ut-\frac{1}{2}\times g{{t}^{2}}\] \[=15\times 4-\frac{1}{4}\times 10\times 16=-20m\] \[\therefore \]distance between them \[60-(-20)=80\,m\]