Answer:
Let\[x\]in the distance travelled by an elevator as the coin reaches the floor of the elevator. \[\therefore \] total distance travelled by the coin in 1 second \[6+x=\frac{1}{2}\times g\times {{t}^{2}}\Rightarrow 6+x=\frac{1}{2}\times 32\times 1\] \[=16\Rightarrow x=16-6=10m\,\,again\,\,x=\frac{1}{2}a{{t}^{2}}\] \[1=\frac{1}{2}\times a\times 1\Rightarrow a=20ft/{{s}^{2}}\]
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