Answer:
Weight of body, \[W=mg=\frac{GMm}{{{R}^{2}}}\] When the diameter or radius of the earth becomes double its present value, the weight of the body will be \[W'=\frac{GMm}{{{(2R)}^{2}}}=\frac{1}{4}W\] i.e., weight will become one-fourth of the present value.
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