Answer:
Mass of the earth, \[M=\frac{4}{3}\pi {{R}^{3}}\rho \] Acceleration due to gravity on the earth's surface, \[g=\frac{GM}{{{R}^{2}}}=\frac{G}{{{R}^{2}}}\times \frac{4}{3}\pi {{R}^{3}}\rho =\frac{4}{3}\pi \rho \mathbf{GR}.\]
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