Answer:
As \[{{g}_{h}}=g\left( 1-\frac{2h}{d} \right)\] and \[{{g}_{d}}=g\left( 1-\frac{d}{h} \right)\] For \[h=d=1km,\]clearly \[{{g}_{d}}>{{g}_{p}}\]. Hence the body will weigh more at a depth of \[\text{1 km}\] below the surface of earth.
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