Answer:
If \[\rho \]is the density of the material, then \[F=G\frac{{{m}_{1}}{{m}_{2}}}{{{(2r)}^{2}}}=G\frac{\frac{4}{3}\pi {{r}^{3}}\rho \times \frac{4}{3}\pi {{r}^{3}}\rho }{(2{{r}^{2}})}=\frac{4}{9}{{\pi }^{2}}{{\rho }^{2}}G{{r}^{4}}\] Clearly, \[F\propto {{r}^{4}}\]
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