Answer:
Let h be the height and t be the time at which wooden block and bullet will meet.
For wooden block: \[s=ut+\frac{1}{2}a{{t}^{2}}\Rightarrow 100-h=\frac{1}{2}g{{t}^{2}}\Rightarrow (1)\] For bullet: In the case of bullet, \[h=100\times t\times \frac{1}{2}g{{t}^{2}}\to (2)\] Substituting (2) in (1) we get \[100-\left( 100t-\frac{1}{2}g{{t}^{2}} \right)=\frac{1}{2}g{{t}^{2}}\] \[100-100+\frac{1}{2}g{{t}^{2}}=\frac{1}{2}g{{t}^{2}}\Rightarrow 100=100t\] \[\Rightarrow t=1s.\]
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