Answer:
When the 6th ball is dropped the positions of the 3rd, 4th and 5th ball from the top are as shown in the figure
the duration for the3rd ball is 3 sec, \[{{h}_{3}}=\frac{1}{2}\times gt_{3}^{2}\] \[=\frac{1}{2}\times 9.8\times 44.1\,m\] the duration for the 4th ball is 2 sec, \[{{h}_{4}}=\frac{1}{2}\times gt_{4}^{2}\] \[=\frac{1}{2}\times 9.8\times 4=19.6\,m\] the duration for the 5th ball is 1 sec, \[{{h}_{5}}\] \[=\frac{1}{2}\times g\times t_{5}^{2}=\frac{1}{2}\times 9.8\times 1=4.9\,m\]
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