question_answer

The value of g on the earths surface is\[\text{98}0\text{ cm}/\text{se}{{\text{c}}^{\text{2}}}\].Its value at a height of 64 km from the earths surface is (a) \[\text{96}0.\text{4}0\,\text{cm}/\text{se}{{\text{c}}^{\text{2}}}\]  (b) \[\text{984}.\text{9}0\,\text{cm}/\text{se}{{\text{c}}^{\text{2}}}\] (c) \[\text{982}.\text{45cm}/\text{se}{{\text{c}}^{\text{2}}}\]   (d) \[\text{977}.\text{55}\,\text{cm}/\text{se}{{\text{c}}^{\text{2}}}\]

Answer:

\[g'=\frac{g{{R}^{2}}}{{{(R=h)}^{2}}}=980\left( \frac{6400}{6400+64} \right)960\,c{{m}^{2}}\]