A) Decreases by 36%
B) Increases by 36%
C) Increases by 64%
D) Decreases by 64%
Correct Answer: A
Solution :
\[F\propto \frac{1}{{{d}^{2}}},d'=d+\frac{25d}{100}=\frac{125d}{100}\] \[\frac{F'}{F}=\frac{{{d}^{2}}}{{{d}^{12}}}\Rightarrow \frac{{{d}^{2}}}{{{\left( \frac{125d}{100} \right)}^{2}}}=\frac{F'}{F}\Rightarrow \] \[F'=\frac{100}{{{25}^{2}}}=0.64\] \[(or)\,\,F'=64%\,F\] i.e., Force decrease by 36%.
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